# Could someone help me work out the geometry for making a scaled wooden windmill?

Asked by noodle_poodle (1593 ) 1 month ago

I need to make a model windmill. I need to make it out of wooden board so that its sturdy. Ideally I’d like it to be octangular and it would taper up slightly (as windmills do) but I have no idea where to start in figuring out how to calculate the taper and the angles to insure that it can have flat walls that taper and meet correctly at the top. Any advice would be greatly appreciated! If I have not explained it properly imagine this, http://en.wikipedia.org/wiki/Shirley_Windmill
but with flat sides instead of round.

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I don’t know what values you have chosen to use to specify your windmill. I am going to assume that you have chosen some base length b for the side of the base octahedron and a for the length of the side of the upper octahedron. I am also going to assume you have specified the slant height h1 joining a and b.

It is convenient to work with the triangle formed by extending the two sides joining the two bases. If we call call h the height of the triangle, then using similar triangles, we get (h – h1)/a = h/b. Solve for h. You can now calculate the base angles using (b/2)/h = tan(base angle).

You can also compute the tilt angle of the walls. First calculate the distance g from a side b to the center of the octahedron, given by (b/2)/g = tan(22.5). Then g/h = cos(tilt angle).

It’s easier than it sounds. Cut the number of boards you want for the walls from the same exact template, tapered at the top. They’ll lean in just as you want. You could try it first with cardboard or construction paper if you want to experiment. I just did it with some scrap paper. It worked. That gives you the tower.

Don’t forget to taper the side cuts, angle will depend on how many sides you decide to use. 22.5 degrees for 8 sides, 15 degrees for 6.

rojo (12191 )

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