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• 2 weeks ago

  What is peak Trick-or-Treating time?

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• 1 month ago

  Is it possible to get a Degree in astrology?

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• 1 month ago

  Anybody have a good pumpkin bread recipe?

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• 1 month ago

  Why is my hot water heater making funny noises?

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• May 19th, 2009

  Would you be my friend if I wore this?

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Answers

• 1 day ago

  Can I use contact lenses that have frozen (and then thawed, perhaps multiple times)?

  I would imagine that it might be ok, but to be certain you should call Acuvue customer service or your eye doctor. You don’t really want to mess around with stuff you put in your eyes.
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• 2 days ago

  What is the recommended daily intake limit of sugar?

  @evegrimm: My parents say: “everything in moderation, including moderation”
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• 3 days ago

  Where can I buy high quality Egyptian cotton bed sheet sets?

  Macy’s and Bed Bath and Beyond are good bets. At BB&B, you can usually get a 20% off discount coupon.
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• 3 days ago

  Why is there Christmas stuff out at Target already?

  I think this sums it up nicely
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• 3 days ago

  How do I calculate capillary entry pressure for a given pore width and and a known surface tension?

  ok, let me see if I can help (no guarantee, especially because I imagine you already know most of this stuff): when you let a drop of liquid fall from a height, it hits the material with a certain speed, let’s call it V. The drop of liquid comes to a stop because the material exerts a force on it. Because we know the initial speed, V, and the final speed can be assumed to be zero, you could calculate the impulse, which is the change in momentum of the drop, or the integral of the force over time. If you can time how long it takes for the drop to come to a complete stop (which would be hard, and probably require a high-speed camera), then you could know the force that’s being exerted between the material and the droplet. Since pressure=force/area, you could use the area of the pores, and figure out the pressure exerted on them by the falling droplet. Of course, the above paragraph is based on basic freshman physics, and doesn’t account for a huge number of different variables that could affect this. On top of that, I don’t exactly understand what capillary pressure is, so I’m not even sure if the approach i described would be useful, in the event that you could put it into practice. I am very interested in learning about this though, if you want to try to explain it, I’d enjoy trying to work out the problem with you.
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