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Calculating molarity.... am I doing it right?
Asked by prioritymail (1630)
September 24th, 2011
The question is:
If the conc of a L of soln is 2 ppm and the mass wt of chemical compound is 300 g, what is the molarity?
What I’m thinking:
Molarity = mol solute / L solution (by definition)
1 mol of chemical compound = 300 g (by definition)
ppm = mg / L (by definition)
Therefore,
2 ppm = x mg / L; x = 2 mg
mol solute = 2 mg * (mol / 300 * 10^6 mg) = 6.67 * 10^6 mol
Molarity = 6.67 * 10^-6 M
Now this seems like a ridiculously small number for an answer to a homework problem. I’m wondering if I did something wrong, particularly regarding extracting the mg of compound from given ppm solution concentration. Thanks in advance for help!
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