## Social Question

# Can you find the trick to solving this math problem?

Asked by LostInParadise (27896)
June 24th, 2020

I thought of this math problem, though I am certainly not the first to think of it. It has a rather simple solution if you think about it the right way.

What is the most numbers that you can choose from 1 to 100 such that no number is twice as great as any other number?

The most natural way to attack this is to choose numbers starting at 1 and skipping over numbers that are twice as great as numbers previously chosen. There is a much slicker way. Start choosing numbers beginning at 100 and move downward. Do you see the trick?

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