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How do I solve a literal equation that contains more than 1 variable, specifically one that contains a fraction?

Asked by emeraldisles (1949points) October 7th, 2011

For instance, I need help on 1. ⅔a-6b=9 solve for a. 2. a + b/4=2 solve for a. 3. x/2+Y=6.solve for y. 4. ⅔a-6b=9 solve for b. 5. a +b/4 =2. solve for b. Please someone break ths down into simple steps. I thought that if your doing a fraction that you multiply everything in the equation by the lcd and then go from there?

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