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Can you find the axis of symmetry of the graph of y = arctan(x) + arctan(6 - x)

Asked by LostInParadise (31920points) June 16th, 2016

For those intrepid enough to have gotten this far I offer two hints, which I have encoded for the benefit of those who wish to tackle this problem without them. You can decode the hints at this site You can of course cheat by using a graphing calculator. That still leaves the question of explaining why it works, which requires only a fairly short explanation and does not require any advanced math.

Bar boivbhf dhrfgvba vf jurgure jr ner hfvat qrterrf be enqvnaf sbe l. Vg znxrf ab qvssrerapr. Jr jvyy trg gur fnzr iregvpny yvar bs flzzrgel. Va snpg, jr pbhyq ercynpr nepgna jvgu nal shapgvba qrsvarq bire nyy gur ernyf naq fgvyy trg gur fnzr nkvf. Jr pbhyq nyfb ercynpr nqqvgvba jvgu zhygvcyvpngvba. Gurer vf abguvat cnegvphyneyl fcrpvny nobhg 6 rvgure. Vs jr hfrq nabgure ahzore jr jbhyq trg nanybtbhf erfhygf sbe n qvssrerag nkvf bs flzzrgel.

Abgvpr gung t(k) = 6 -k vf frys-vairefr. Vs jr pnyy gur shapgvba jr ner jbexvat jvgu s(k), jung vf gur inyhr bs s(6-k)?

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