Why my "send to a friend form" only works in safari?

Asked by pasoma89 (1) April 2nd, 2009

Please help me!!!

<?php

if(count($_POST)) {

foreach(array(‘friendmail1’,‘friendmail2’,‘friendmail3’,‘email’,‘name’,‘dia_hora’) as $key) $_POST[$key] = strip_tags($_POST[$key]);
if(!is_secure($_POST)) { die(“Seguridad”);}

$emailto = “info@mysite.com”;

$esubject = “Una recomendación del sitio web se ha realizado”;

$emailtext = ”
$_POST[name] ha utilizado el formulario: invite a sus amigos. Su e-mail es $_POST[email]. Y la fecha indicada para la reunión fue: $_POST[dia_hora] .

Con las siguientes personas:

$_POST[friendmail1]
$_POST[friendmail2]
$_POST[friendmail3]

”;

@mail(”$emailto”, $esubject, $emailtext, “From: $_POST[email]”);

$thankyou = “thanks.html”;

$tsubject = ”$_POST[name] te recomienda mysite”;

$ttext = ”
hi

check this out http://www.mysite.com

Atte

Tu amigo(a),

$_POST[name]
$_POST[email]

”;

@mail(”$_POST[friendmail1],$_POST[friendmail2],$_POST[friendmail3]”, $tsubject, $ttext, “FROM: $_POST[email]”);

header(“Location: $thankyou”);
exit;

}

function is_secure($ar) {
$reg = ”/(Content-Type|Bcc|MIME-Version|Content-Transfer-Encoding)/i”;
if(!is_array($ar)) { return preg_match($reg,$ar);}
$incoming = array_values_recursive($ar);
foreach($incoming as $k=>$v) if(preg_match($reg,$v)) return false;
return true;
}

function array_values_recursive($array) {
$arrayValues = array();
foreach ($array as $key=>$value) {
if (is_scalar($value) || is_resource($value)) {
$arrayValues[] = $value;
$arrayValues[] = $key;
}
elseif (is_array($value)) {
$arrayValues[] = $key;
$arrayValues = array_merge($arrayValues, array_values_recursive($value));
}
}
return $arrayValues;
}
?>