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john65pennington's avatar

How many pieces of candy corn would be in this fish bowl?

Asked by john65pennington (29235points) October 31st, 2011

The bowl is 7 inches tall and 16 inches in diameter. This is a contest at a local department store. The problem lies within the three pieces of candy corn taped to the top of the bowl. These pieces are half-hidden, so there may be other pieces underneath each one. I have my own guess at the number of pieces inside the bowl. Question: so, Fluther mathematicians, what is your guess as to the number of pieces of candy corn in the fish bowl? Contest ends tonight at midnight….naturally.

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7 Answers

Adirondackwannabe's avatar

Is it just candy corn or a mix?

john65pennington's avatar

Only candy corn.

42? That would cover just the bottom row of candy corn inside the bowl.

Mariah's avatar

The volume of an ellipsoid is 4/3*pi*a*b*c where a, b, and c are the radii in the x, y, and z directions. Your x and y radii are 8 inches and your z radius is 3.5 inches, so the volume in the bowl should be about 938 cubic inches. I’ll round that down to 900 because a fish bowl is not a perfect ellipsoid. I’d peg candy corn at about ¾” tall, 3/8” wide, ¼” thickness, and approximately triagular-prism shaped. The volume of a triangular prism is ½*b*h*l so that puts candy corn at about .035 cubic inches apiece. Assuming perfect space useage efficiency that equals about 25,714 pieces of candy corn but of course there’ll be lots of empty space in between pieces so I’d guess maybe ⅔ of that, which is 17,143 pieces of candy corn…...still seems like a hell of a high number though, doesn’t it?

Adirondackwannabe's avatar

@Mariah That sounds a little high. I was going from a 24 ounce bag of candly corn mix I have on my desk. It has 255 pieces. But some are fairly sizeable.

Hibernate's avatar

You should tell us the number when the contest end :D

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