# How do you go about adding polynomials with fractions in parantheses?

The problem is( 1/16x^2+1/8)+(¼x^2–3/10x-½). The answer is supposed to be 5/16x^2–3/10x-3/8. All I can figure out is that the numbers/fractions all need to be changed into least common denominator. Have no idea how to get to the next step to get this answer?Help.

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## 4 Answers

Response moderated (Writing Standards)

No they don’t need to be to the LCD – that rule is for adding, not multiplying.

Your problem written in your post is very easy.

(A +B) (C+D+E) = AC+AD+AE+BC+BD+BE = 1/64X^2…

@Charles he IS doing adding.

Okay, lets do an easier one:

(⅓x + 2/5) + (¾x + ½)

Take the “x terms.” These are ⅓x and ¾x Lets get common denominators:

⅓x = 4/12x

¾x = 9/12x

4/12x + 9/12x = (4/12 + 9/12)x = 13/12x

Take the numbers. These are 2/5 and ½. Lets get common denominators:

2/5 = 4/10

½ = 5/10

2/5 + ½ = 4/10 + 5/10 = 9/10

So, the total is

13/12x + 9/10

————————————————————————————————————————————————————-

Okay, lets make it a bit harder.

(1/5x^2 + ⅓x + 2/5) + (⅔x^2 + ¾x + ½)

Take the “x^2 terms.” These are 1/5x^2 and ⅔x^2 Lets get common denominators:

1/5x^2 = 3/15x^2

⅔x^2 = 10/15x^2

3/15x^2 + 10/15x^2 = (3/15 + 10/15)x^2 = 13/15x^2

Take the “x terms.” These are ⅓x and ¾x Lets get common denominators:

⅓x = 4/12x

¾x = 9/12x

4/12x + 9/12x = (4/12 + 9/12)x = 13/12x

Take the numbers. These are 2/5 and ½. Lets get common denominators:

2/5 = 4/10

½ = 5/10

4/10 + 5/10 = 9/10

So, the total is

13/15x^2 + 13/12x + 9/10

———————————————————————————————————————-

Hope this helps. If you want more explanation, please ask.

disregard the parenthesies, and only add like terms, coefficients with the same variables, don’t add 3a to 4b or 5a^2 to 6a, order of operations

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