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emeraldisles's avatar

How do I solve a literal equation that contains more than 1 variable, specifically one that contains a fraction?

Asked by emeraldisles (1949points) October 7th, 2011

For instance, I need help on 1. ⅔a-6b=9 solve for a. 2. a + b/4=2 solve for a. 3. x/2+Y=6.solve for y. 4. ⅔a-6b=9 solve for b. 5. a +b/4 =2. solve for b. Please someone break ths down into simple steps. I thought that if your doing a fraction that you multiply everything in the equation by the lcd and then go from there?

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5 Answers

Mariah's avatar

We’re not supposed to tell people exactly how to do their homework here on Fluther, but I can point you in the right direction.

If the equation has more than one variable, but you only have one equation to go by, then you can only solve for the desired variable in terms of the other variable. You treat a fraction coefficient the same way you’d treat any other coefficient.

Let me know if this settles it for you or if you still need help.

Ivan's avatar

“I thought that if your doing a fraction that you multiply everything in the equation by the lcd and then go from there?”

Yup. Just do that. For instance, you would multiply both sides of the first equation by 3. Once that is done, isolate the desired variable on one side of the equation.

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emeraldisles's avatar

Well thankyou. I guess I was on the right track. Im not trying to get people to do my homework which just ticks me off. I’m just trying to get the steps right so I get the right answer.

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